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31〜40本ノック

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|| データサイエンス100本ノック(構造化データ加工編) SQL編

| S-031 ★

レシート明細テーブル(receipt)に対し、店舗コード(store_cd)ごとに売上金額 (amount)の標本標準偏差を計算し、降順でTOP5を表示せよ。

select
    store_cd
    , stddev(amount) as std
from 
    `100knocks.receipt`
group by 
    store_cd
order by 
    std desc
limit 5
;

| S-032 ★

レシート明細テーブル(receipt)の売上金額(amount)について、25%刻みでパーセンタイル値を求めよ。

# BigQuery
select
    store_cd
    , max(min) as min
    , max(q1) as q1
    , max(q2) as q2
    , max(q3) as q3
    , max(max) as max
from (
    select
        store_cd
        , percentile_cont(amount, 0.0)  over w as min
        , percentile_cont(amount, 0.25) over w as q1
        , percentile_cont(amount, 0.5)  over w as q2
        , percentile_cont(amount, 0.75) over w as q3
        , percentile_cont(amount, 1.0)  over w as max
    from 
        `100knocks.receipt`
    window
        w as (partition by store_cd)
) as statistic
group by store_cd
;
# PostgreSQL
SELECT
    PERCENTILE_CONT(0.25) WITHIN GROUP(ORDER BY amount) as amount_25per,
    PERCENTILE_CONT(0.50) WITHIN GROUP(ORDER BY amount) as amount_50per,
    PERCENTILE_CONT(0.75) WITHIN GROUP(ORDER BY amount) as amount_75per,
    PERCENTILE_CONT(1.0) WITHIN GROUP(ORDER BY amount) as amount_100per
FROM receipt

| S-033 ★

レシート明細テーブル(receipt)に対し、店舗コード(store_cd)ごとに売上金額 (amount)の平均を計算し、330以上のものを抽出せよ。

select
    store_cd
    , avg(amount) as mean
from 
    `100knocks.receipt`
group by 
    store_cd
having 
    mean > 330
;

| S-034 ★

レシート明細テーブル(receipt)に対し、顧客ID(customer_id)ごとに売上金額 (amount)を合計して全顧客の平均を求めよ。ただし、顧客IDが"Z"から始まるのものは 非会員を表すため、除外して計算すること。

-- select
--     customer_id
--     , sum(amount) as ttl_amount
-- from `100knocks.receipt`
-- where not regexp_contains(customer_id, r'^Z')
-- group by customer_id
-- ;

with
    customer_tb as(
        select
            customer_id
            , sum(amount) as ttl_amount
        from 
            `100knocks.receipt`
        where 
            not regexp_contains(customer_id, r'^Z')
        group by 
            customer_id
    )
select 
    avg(ttl_amount) 
from 
    customer_tb
;
# PostgreSQL
WITH customer_amount AS (
    SELECT customer_id, SUM(amount) AS sum_amount
    FROM receipt
    WHERE customer_id not like 'Z%'
    GROUP BY customer_id
)
SELECT AVG(sum_amount) from customer_amount

| S-035 ★★

レシート明細テーブル(receipt)に対し、顧客ID(customer_id)ごとに売上金額 (amount)を合計して全顧客の平均を求め、平均以上に買い物をしている顧客を抽出せよ。ただし、顧客IDが"Z"から始まるのものは非会員を表すため、除外して計算すること。なお、データは10件だけ表示させれば良い。

with
    customer_tb as(
        select
            customer_id
            , sum(amount) as ttl_amount
        from 
            `100knocks.receipt`
        where 
            not regexp_contains(customer_id, r'^Z')
        group by 
            customer_id
    )
select
    customer_id
    , ttl_amount
from 
    customer_tb
where 
    ttl_amount > (select avg(ttl_amount) from customer_tb)
limit 10
;

| S-036 ★

レシート明細テーブル(receipt)と店舗テーブル(store)を内部結合し、レシート明細 テーブルの全項目と店舗テーブルの店舗名(store_name)を10件表示させよ。

select
    *
from
    `100knocks.receipt`
left join
    (select store_cd, store_name from `100knocks.store`) as store
using(store_cd)
limit 10
;

| S-037 ★

商品テーブル(product)とカテゴリテーブル(category)を内部結合し、商品テーブル の全項目とカテゴリテーブルの小区分名(category_small_name)を10件表示させよ。

select
    *
from
    `100knocks.product` p
left join
    (select category_major_cd, category_medium_cd, category_small_cd, category_small_name from `prj-test3.100knocks.category`) as c
using(category_major_cd, category_medium_cd, category_small_cd)

-- on 
--         p.category_major_cd=c.category_major_cd
--     and p.category_medium_cd=c.category_medium_cd
--     and p.category_small_cd=c.category_small_cd

limit 10
;
select
    p.*
    , c.category_small_name
from 
    `100knoks.product` p
join 
    `100knoks.category` c using(category_small_cd)
limit 10
;

| S-038 ★

顧客テーブル(customer)とレシート明細テーブル(receipt)から、各顧客ごとの売上 金額合計を求めよ。ただし、売上実績がない顧客については売上金額を0として表示させ ること。また、顧客は性別コード(gender_cd)が女性(1)であるものを対象とし、非会員(顧客IDが"Z"から始まるもの)は除外すること。なお、結果は10件だけ表示させれば良い。

-- with customer_amount as(
--     select
--         customer_id
--         , sum(amount) as ttl_amount
--     from `prj-test3.100knocks.receipt`
--     group by customer_id
-- )
-- select
--     customer_id
--     , coalesce(ttl_amount, 0) as ttl_amount
-- from `prj-test3.100knocks.customer`
-- join customer_amount using(customer_id)
-- -- where
-- order by ttl_amount
-- ;

select
    customer_id
    , customer_name
    , sum(amount) as ttl_amount
from 
    `100knocks.customer` c
join 
    `100knocks.receipt` r using(customer_id)
where
        customer_id not like'Z%'
    and gender_cd = 1
group by
    customer_id
    , customer_name
limit 10
;

Cf. SQL関数coalesceの使い方と読み方 - Sppirits

| S-039 ★

レシート明細テーブル(receipt)から売上日数の多い顧客の上位20件と、売上金額合計の多い顧客の上位20件を抽出し、完全外部結合せよ。ただし、非会員(顧客IDが"Z"から始まるもの)は除外すること。

select
    customer_id
    , count(distinct sales_ymd) as days
    , sum(amount) as amount
from 
    `100knocks.receipt`
where 
    customer_id not like 'Z%'
group by 
    customer_id
order by  
    days desc  
    , amount desc
limit 20
;

| S-040 ★

全ての店舗と全ての商品を組み合わせると何件のデータとなるか調査したい。店舗 (store)と商品(product)を直積した件数を計算せよ。

-- select
--     (select
--         count(distinct store_cd)
--     from `100knocks.store`)
--     union all
--     (select
--         count(distinct product_cd)
--     from `100knocks.product`) as ttl_record

select
    count(*)
from 
    `100knocks.store`
cross join 
    `100knocks.product`
;

cross join を知ると join が書きやすくなるよ、という話 - Feedforce Developer Blog